[2013-Mar-26] 2927

Blame Quintushalls for this.

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Rockchurch
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Joined: Sun Sep 04, 2011 6:21 pm

Re: [2013-03-26] 2927

Post by Rockchurch »

You're all overthinking it.

y = 0x + 0.5

Image

UnicornBacon

Re: [2013-03-26] 2927

Post by UnicornBacon »

so it wouldnt be a line. it would be a single plot point.

at the rightmost part of the graph, only a single point from the top.

where 0 on the emptyness line would indicate totally filled, one unit from the top would indicate a single point.
the width of the graph is 100% so the point would be in the rightmost aspect of said graph.

am i doing it right?

Maze1125
Posts: 9
Joined: Sun Jun 10, 2012 8:46 pm

Re: [2013-03-26] 2927

Post by Maze1125 »

Rockchurch wrote:You're all overthinking it.

y = 0x + 0.5
Two questions:
1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?
2) Why have you written the equation as y = 0x + 0.5? You do know that's just the same as y = 0.5, right?

As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.

Rockchurch
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Joined: Sun Sep 04, 2011 6:21 pm

Re: [2013-03-26] 2927

Post by Rockchurch »

Maze1125 wrote:As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.
No, it's unanswerable, only if you choose to ignore the most obvious interpretation of 'emptiness'.
Maze1125 wrote: 1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?
See above.

TheOtherOne
Posts: 1
Joined: Tue Mar 26, 2013 7:04 pm

Re: [2013-03-26] 2927

Post by TheOtherOne »

The answer is a single point at (0, inf). A point has no area so it does not add width or take away from the emptiness. The graph of a single point has 0 width and is infinitely empty.

It can't be anything other than a single data point, because it's referring to this specific graph, which after submitting, has a constant width and area (unless you submitted an animation or something).

EDIT: Actually windytan's answer is a little more correct than mine. Just depends on how you define your units.
Last edited by TheOtherOne on Tue Mar 26, 2013 11:50 pm, edited 1 time in total.

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ThePeople
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Re: [2013-03-26] 2927

Post by ThePeople »

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Oldrac the Chitinous
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Re: [2013-03-26] 2927

Post by Oldrac the Chitinous »

Ah, good. I don't want to abuse my pony power. Well, any more than what's inherent in using it at all.
Thanks for stepping up, ThePeople.
Police said they spent some time working out if they could charge the man with being armed with a weapon, as technically he was armed with part of a fish.

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Lethal Interjection
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Re: [2013-03-26] 2927

Post by Lethal Interjection »

Rockchurch wrote:You're all overthinking it.

y = 0x + 0.5
Hahaha.
They (you) are, aren't they (you).

Cocio_16

Re: [2013-03-26] 2927

Post by Cocio_16 »

Why the hell the width of this graph would change ? It’s a constant. Thus, the emptiness will be a constant too.

a = width
b = emptiness
the values of the width and the emptiness equals whatever you want.

Put a point at (a,b).

A point as no width.

You get 100%

Cocio_16

Re: [2013-03-26] 2927

Post by Cocio_16 »

Cocio_16 wrote:Why the hell the width of this graph would change ? It’s a constant. Thus, the emptiness will be a constant too.

a = width
b = emptiness
the values of the width and the emptiness equals whatever you want.

Put a point at (a,b).

A point as no width.

You get 100%
Fuck I read the thread before I posted this. Why I didn’t see two person had already give the same answer.

Bahgragblerable

Re: [2013-03-26] 2927

Post by Bahgragblerable »

Hm, what if you drew a line down? Into the negative axis that is...maybe one or both? Granted the space given doesn't allow you to do it nicely but you could make do with the margins of the page.


I'm sorry I'm doped up on cayenne and it's late, but I believe this debate is what the comic means by "Destroy a math class". We'll start feeding on each other soon.

Zarkov!

Re: [2013-03-26] 2927

Post by Zarkov! »

Completely fill the graph area with white-out?

Guest

Re: [2013-03-26] 2927

Post by Guest »

Why not just have a graph that goes negative?

Easiest 100pts in a test ever!

Maze1125
Posts: 9
Joined: Sun Jun 10, 2012 8:46 pm

Re: [2013-03-26] 2927

Post by Maze1125 »

Rockchurch wrote:
Maze1125 wrote:As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.
No, it's unanswerable, only if you choose to ignore the most obvious interpretation of 'emptiness'.
I see at least two options for "emptiness" neither of which is inherently more obvious than the other.
It could be actual-blank-space/potential-blank-space or it could simply be actual-blank-space.
If the former, the the graph is a horizontal line at 1 or, if you consider the line to have some thickness, slightly below 1.
If the latter, the graph is an increasing straight-line from (0,0).
Maze1125 wrote: 1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?
See above.
[/quote]
I see nothing above that answers that question.

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ThePeople
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Re: [2013-03-26] 2927

Post by ThePeople »

You people need to look at the picture a lot more closely. You don't seem to understand it.

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