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[2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 3:19 pm
by GollyRojer
http://www.smbc-comics.com/comic/puzzle-time

I dunno, something's wrong with the artwork. I can't read any of them.

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 3:32 pm
by rpresser
y = 0.9303569123 x^7 - 22.23193879 x^6 + 207.829112 x^5 - 961.3816793 x^4 + 2289.732664 x^3 - 2625.385296 x^2 + 1111.506783 x + 0.00001611345942

Graph on Wolfram Alpha

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 4:53 pm
by IRLPinkiePie
i got it as (521/560)x^7 - (2587/90)x^6 + (43291/120)x^5 - (170393/72)x^4 + (2085781/240)x^3 - (6369907/360)x^2 + (638962/35)x - 7219, but to each their own, i guess~

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 5:23 pm
by Woom
My version is essentially the same, but rendered as:
( 4689 * n^6 - 112049 * n^5 + 1047459 * n^4 - 4845365 * n^3 + 11540256 * n^2 - 13231946 * n + 5601996 ) * n / 5040

(The next term is 8666.)

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 5:54 pm
by Cryft
https://oeis.org/search?q=0%2C1%2C4%2C- ... &go=Search

If he was just randomly thinking "I wonder what sequence hasn't been used before..." then he really nailed it.

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 9:52 pm
by King of Ferrets
Psssh, that's easy.

f(0) = 1
f(x) = 0 when x != 0

f(x-1)*1+f(x-2)*4+f(x-3)*-13+f(x-4)*-133+f(x-5)*52+f(x-6)*53+f(x-7)*-155

See? Simple! <.< >.>

Re: [2017 4-18] Puzzle Time

Posted: Tue Apr 18, 2017 10:20 pm
by Guest
I'm personally fond of the form
f(n) = ₙC₁ + 2 ₙC₂ − 22 ₙC₃ − 61 ₙC₄ + 552 ₙC₅ − 1940 ₙC₆ + 4689 ₙC₇.

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 1:18 am
by codetaku
Woom wrote:My version is essentially the same, but rendered as:
( 4689 * n^6 - 112049 * n^5 + 1047459 * n^4 - 4845365 * n^3 + 11540256 * n^2 - 13231946 * n + 5601996 ) * n / 5040

(The next term is 8666.)
I just used matlab to get an estimate of the coefficients via polyfit (obviously I had to specify degree 7 since that's the "simplest" polynomial that fits these parameters, though there are infinitely many polynomials of greater degree that also fit this sequence).

Anyway, I concur that the next term is 8666 in the case that we assume the simplest possible pattern fit to the sequence. But let's be honest, there's no author intention because I doubt zach knows how to fit a polynomial to a set of points :P

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 7:34 am
by ThePaulanator
Someone should definitely submit it on oeis as the weinersmith numbers.

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 8:34 am
by cmena2702
The obvious solution is the sequence defined as follows:

The sequence an is defined by:
{a1 = 0
a2 = 1
a3 = 4
a4 = -13
a5 = -133
a6 = 52
a7 = 53
a8 = -155} for an from N.

Yes, I am a dickhead. My area is pure mathematics; answers that are technically true but completely meaningless are what I do best.

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 1:01 pm
by codetaku
cmena2702 wrote:The obvious solution is the sequence defined as follows:

The sequence an is defined by:
{a1 = 0
a2 = 1
a3 = 4
a4 = -13
a5 = -133
a6 = 52
a7 = 53
a8 = -155} for an from N.

Yes, I am a dickhead. My area is pure mathematics; answers that are technically true but completely meaningless are what I do best.
I am willing to believe that your area is pure mathematics because anyone *sane* would be 0-indexing this sequence ;P but regardless, you seem to have missed the comma+ellipsis in the original sequence. This directly implies that the sequence has length greater than 8. Many even use it to imply that the sequence is infinite (perhaps repeating, but still infinite), but at the very least, not even a theoretical mathematician would put an ellipsis after the end of a finite sequence.

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 3:43 pm
by DrHammer
I'll take my 14 points please.

{n∈Z|(∃x∈N)[n=H(x-1)+3H(x-2)-17H(x-3)-120H(x-4)+185H(x-5)+H(x-6)-208H(x-7)]}
Where Z are the integers, N is the set of natural numbers, and H is the Heaviside function.

Re: [2017 4-18] Puzzle Time

Posted: Wed Apr 19, 2017 6:37 pm
by codetaku
DrHammer wrote:I'll take my 14 points please.

{n∈Z|(∃x∈N)[n=H(x-1)+3H(x-2)-17H(x-3)-120H(x-4)+185H(x-5)+H(x-6)-208H(x-7)]}
Where Z are the integers, N is the set of natural numbers, and H is the Heaviside function.
Hahah, okay, I bow to you, that was a perfect answer.

And all future elements are -155. So elegant! You won't even introduce nonintegers!

Re: [2017 4-18] Puzzle Time

Posted: Thu Feb 16, 2023 8:35 pm
by BillMemerik
Hi. There's another kind of puzzle, such as wooden puzzle models, a great way to show your creative side as well as having a beautiful object to display at home or in the office. Not only are they fun and challenging to build, they are also designed with all the mechanics needed to make them move like the real objects they represent.

Wooden model kits make a great gift for friends and family who appreciate creating functional works of art.

Re: [2017 4-18] Puzzle Time

Posted: Thu Feb 16, 2023 8:42 pm
by Monisa
When you assemble wooden models the creative side of your brain gets the exercise it needs. Creating a scale model is a whole art, and while you can follow the instructions exactly or paint the model in a historically accurate style, you can also go beyond and bring your own style. There is no right or wrong way to create a model - it all depends on your personal preferences and what you hope to get out of it.