[2013-Mar-26] 2927

Blame Quintushalls for this.

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Re: [2013-03-26] 2927

Postby Rockchurch » Tue Mar 26, 2013 10:07 pm

You're all overthinking it.

y = 0x + 0.5

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Re: [2013-03-26] 2927

Postby UnicornBacon » Tue Mar 26, 2013 10:16 pm

so it wouldnt be a line. it would be a single plot point.

at the rightmost part of the graph, only a single point from the top.

where 0 on the emptyness line would indicate totally filled, one unit from the top would indicate a single point.
the width of the graph is 100% so the point would be in the rightmost aspect of said graph.

am i doing it right?
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Re: [2013-03-26] 2927

Postby Maze1125 » Tue Mar 26, 2013 10:36 pm

Rockchurch wrote:You're all overthinking it.

y = 0x + 0.5

Two questions:
1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?
2) Why have you written the equation as y = 0x + 0.5? You do know that's just the same as y = 0.5, right?

As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.
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Re: [2013-03-26] 2927

Postby Rockchurch » Tue Mar 26, 2013 10:45 pm

Maze1125 wrote:As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.


No, it's unanswerable, only if you choose to ignore the most obvious interpretation of 'emptiness'.

Maze1125 wrote:1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?


See above.
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Re: [2013-03-26] 2927

Postby TheOtherOne » Tue Mar 26, 2013 11:46 pm

The answer is a single point at (0, inf). A point has no area so it does not add width or take away from the emptiness. The graph of a single point has 0 width and is infinitely empty.

It can't be anything other than a single data point, because it's referring to this specific graph, which after submitting, has a constant width and area (unless you submitted an animation or something).

EDIT: Actually windytan's answer is a little more correct than mine. Just depends on how you define your units.
Last edited by TheOtherOne on Tue Mar 26, 2013 11:50 pm, edited 1 time in total.
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Re: [2013-03-26] 2927

Postby ThePeople » Tue Mar 26, 2013 11:49 pm

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Re: [2013-03-26] 2927

Postby Oldrac the Chitinous » Wed Mar 27, 2013 1:26 am

Ah, good. I don't want to abuse my pony power. Well, any more than what's inherent in using it at all.
Thanks for stepping up, ThePeople.
Police said they spent some time working out if they could charge the man with being armed with a weapon, as technically he was armed with part of a fish.
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Re: [2013-03-26] 2927

Postby Lethal Interjection » Wed Mar 27, 2013 1:50 am

Rockchurch wrote:You're all overthinking it.

y = 0x + 0.5



Hahaha.
They (you) are, aren't they (you).
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Re: [2013-03-26] 2927

Postby Cocio_16 » Wed Mar 27, 2013 3:39 am

Why the hell the width of this graph would change ? It’s a constant. Thus, the emptiness will be a constant too.

a = width
b = emptiness
the values of the width and the emptiness equals whatever you want.

Put a point at (a,b).

A point as no width.

You get 100%
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Re: [2013-03-26] 2927

Postby Cocio_16 » Wed Mar 27, 2013 3:58 am

Cocio_16 wrote:Why the hell the width of this graph would change ? It’s a constant. Thus, the emptiness will be a constant too.

a = width
b = emptiness
the values of the width and the emptiness equals whatever you want.

Put a point at (a,b).

A point as no width.

You get 100%


Fuck I read the thread before I posted this. Why I didn’t see two person had already give the same answer.
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Re: [2013-03-26] 2927

Postby Bahgragblerable » Wed Mar 27, 2013 5:48 am

Hm, what if you drew a line down? Into the negative axis that is...maybe one or both? Granted the space given doesn't allow you to do it nicely but you could make do with the margins of the page.


I'm sorry I'm doped up on cayenne and it's late, but I believe this debate is what the comic means by "Destroy a math class". We'll start feeding on each other soon.
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Re: [2013-03-26] 2927

Postby Zarkov! » Wed Mar 27, 2013 7:02 am

Completely fill the graph area with white-out?
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Re: [2013-03-26] 2927

Postby Guest » Wed Mar 27, 2013 10:33 am

Why not just have a graph that goes negative?

Easiest 100pts in a test ever!
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Re: [2013-03-26] 2927

Postby Maze1125 » Wed Mar 27, 2013 11:52 am

Rockchurch wrote:
Maze1125 wrote:As has already been explained, the question is unanswerable as it stands as "emptiness", as used, has not be clearly defined.


No, it's unanswerable, only if you choose to ignore the most obvious interpretation of 'emptiness'.

I see at least two options for "emptiness" neither of which is inherently more obvious than the other.
It could be actual-blank-space/potential-blank-space or it could simply be actual-blank-space.
If the former, the the graph is a horizontal line at 1 or, if you consider the line to have some thickness, slightly below 1.
If the latter, the graph is an increasing straight-line from (0,0).

Maze1125 wrote:1) Why are you arbitrarily defining the area below the line as "not empty"? What has it been filled with?


See above.
[/quote]
I see nothing above that answers that question.
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Re: [2013-03-26] 2927

Postby ThePeople » Wed Mar 27, 2013 12:55 pm

You people need to look at the picture a lot more closely. You don't seem to understand it.
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